ML_course/assignment 1/iml_assignment1_unsolved.ipynb
2023-03-27 18:13:27 +02:00

285 lines
7.1 KiB
Plaintext

{
"nbformat": 4,
"nbformat_minor": 0,
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.8.3"
},
"colab": {
"provenance": []
}
},
"cells": [
{
"cell_type": "markdown",
"metadata": {
"id": "whjkuflGLNWu"
},
"source": [
"# Fibonacci Solver\n",
"\n",
"The Fibonacci Sequence is the series of numbers:\n",
"\n",
"` 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... `\n",
"\n",
"The next number is found by adding up the two numbers before it:\n",
"\n",
"the `2` is found by adding the two numbers before it `(1+1)`,\n",
"the `3` is found by adding the two numbers before it `(1+2)`,\n",
"the `5` is `(2+3)`,\n",
"and so on!\n",
"\n",
"## Coding it up in Python\n",
"Just initialize to variables with the first two numbers of the Fibonacci sequence. Then add them up and print the result.\n"
]
},
{
"cell_type": "code",
"metadata": {
"id": "p58ac2HULNWv"
},
"source": [],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "xSyPoS1bLNWy"
},
"source": [
"You now need to do this multiple times, so you need a ***loop***\n",
"To use a loop you need to know how many times you want to loop for. \n",
"For now, create a loop that prints **20** numbers (from 0 to 19). To do this in python you can create a ***for loop*** using the `range` function which will run the function for every number in the range.\n",
"(TIP: Python is a ***0 based*** language which means it starts counting from 0 not 1 as a human normally would.)"
]
},
{
"cell_type": "code",
"metadata": {
"id": "tTsWxVxMLNWy"
},
"source": [],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "INNU9p8zLNW0"
},
"source": [
"Now use the loop to compute the first 20 elements of the Fibonacci sequence."
]
},
{
"cell_type": "code",
"metadata": {
"id": "4Hf59jqgLNW1"
},
"source": [],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "bScJ-6tULNW3"
},
"source": [
"If you managed it till here great job!\n",
"Is seems to work great so far, but you need to store these numbers so you can reference them when needed."
]
},
{
"cell_type": "markdown",
"metadata": {
"id": "1VhirrXpLNW3"
},
"source": [
"Create an empty ***array*** called `fibonacci` and then append the elements of the sequence to it."
]
},
{
"cell_type": "code",
"metadata": {
"id": "thTMoVY2LNW3"
},
"source": [],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "6nlc_cC7LNW5"
},
"source": [
"If everything worked according to the plan, you should be able to access any of the first 20 elements of the Fibonacci sequence at will.\n",
"\n",
"eg `fibonacci[0]` would get us the first item in the array whilst `fibonacci[9]` would get us the tenth item (remember Python is 0 based so you always need to take 1 away from the number you need)"
]
},
{
"cell_type": "code",
"metadata": {
"id": "yEKa7pAuLNW6"
},
"source": [
"fibonacci[0]"
],
"execution_count": null,
"outputs": []
},
{
"cell_type": "code",
"metadata": {
"id": "1wbxOVnELNW7"
},
"source": [
"fibonacci[9]"
],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "50FpCM7CLNW9"
},
"source": [
"So now you know how to get at the index, you need to know which index values are asked for by the user.\n",
"Lets get some input from the user."
]
},
{
"cell_type": "markdown",
"source": [
"Get the first index from the user"
],
"metadata": {
"id": "5Vp9iO2r2e2S"
}
},
{
"cell_type": "code",
"source": [],
"metadata": {
"id": "Zj6mnXCI2mNo"
},
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"source": [
"Get the second index from the user"
],
"metadata": {
"id": "9LDXbzP02rFa"
}
},
{
"cell_type": "code",
"metadata": {
"id": "wqbTuR2TLNXA"
},
"source": [],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"source": [
"Print the received inputs and their types"
],
"metadata": {
"id": "EK9FMjJV22x9"
}
},
{
"cell_type": "code",
"metadata": {
"id": "xfy81HrsLNXC"
},
"source": [],
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "ttb_0MejLNXE"
},
"source": [
"The value received from input will be treated as a string type, you need to convert this to a number so python knows to treat it as one."
]
},
{
"cell_type": "code",
"source": [],
"metadata": {
"id": "RwVoHTLn6QvB"
},
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"source": [
"Print the type of the transformed variables."
],
"metadata": {
"id": "pxKx8gKy2-eh"
}
},
{
"cell_type": "code",
"source": [],
"metadata": {
"id": "dN_EzHKr3GmO"
},
"execution_count": null,
"outputs": []
},
{
"cell_type": "markdown",
"metadata": {
"id": "CRuAEA7KLNXE"
},
"source": [
"Now you have all the parts you need to make this work. \n",
"\n",
"* The user should be prompted \"How many results would you like?\"\n",
"* The program should read the users preference, e.g. 20, and then compute the list of elements up to this number.\n",
"* Then the program should ask the user for 2 indexes within the list of the calculated Fibonacci sequence\n",
"* Finally it should print the summation of their values.\n",
"\n",
"Time to put it together:"
]
},
{
"cell_type": "code",
"metadata": {
"id": "ukW0WUA7LNXE"
},
"source": [],
"execution_count": null,
"outputs": []
}
]
}