54 lines
1.5 KiB
Python
54 lines
1.5 KiB
Python
# -*- coding: utf-8 -*-
|
|
# SPDX-FileCopyrightText: : 2020-2023 The PyPSA-Eur Authors
|
|
#
|
|
# SPDX-License-Identifier: MIT
|
|
|
|
"""
|
|
Build industrial energy demand per node.
|
|
"""
|
|
|
|
import pandas as pd
|
|
|
|
if __name__ == "__main__":
|
|
if "snakemake" not in globals():
|
|
from helper import mock_snakemake
|
|
|
|
snakemake = mock_snakemake(
|
|
"build_industrial_energy_demand_per_node",
|
|
simpl="",
|
|
clusters=48,
|
|
planning_horizons=2030,
|
|
)
|
|
|
|
# import EU ratios df as csv
|
|
fn = snakemake.input.industry_sector_ratios
|
|
industry_sector_ratios = pd.read_csv(fn, index_col=0)
|
|
|
|
# material demand per node and industry (kton/a)
|
|
fn = snakemake.input.industrial_production_per_node
|
|
nodal_production = pd.read_csv(fn, index_col=0)
|
|
|
|
# energy demand today to get current electricity
|
|
fn = snakemake.input.industrial_energy_demand_per_node_today
|
|
nodal_today = pd.read_csv(fn, index_col=0)
|
|
|
|
# final energy consumption per node and industry (TWh/a)
|
|
nodal_df = nodal_production.dot(industry_sector_ratios.T)
|
|
|
|
# convert GWh to TWh and ktCO2 to MtCO2
|
|
nodal_df *= 0.001
|
|
|
|
rename_sectors = {
|
|
"elec": "electricity",
|
|
"biomass": "solid biomass",
|
|
"heat": "low-temperature heat",
|
|
}
|
|
nodal_df.rename(columns=rename_sectors, inplace=True)
|
|
|
|
nodal_df["current electricity"] = nodal_today["electricity"]
|
|
|
|
nodal_df.index.name = "TWh/a (MtCO2/a)"
|
|
|
|
fn = snakemake.output.industrial_energy_demand_per_node
|
|
nodal_df.to_csv(fn, float_format="%.2f")
|